When the current in a coil charges from 2A to 4A in 0.05 s, emf of 8 volt is induced in the coil. The coefficient of self induction of the coil is -

Options

A. 0.1 henry
B. 0.2 henry
C. 0.4 henry
D. 0.8 henry

Answer

B

Explanation

`epsilon = M(di)/(dt)` or `8=M[((4-2))/(0.05)]`
`therefore M=(8xx0.05)/(2)=0.2` henry