Aconductor of lengfht 0.4 m is moving with a speed of 7 m/s perpendicular to a magnetic field of intensity` 0.9 Wb//m^(2)` .The induced emf across the coduct is

Options

A. 1.26 V
B. 2.52 V
C. 5.04 V
D. 25.2 V

Answer

B

Explanation

Length of conductor `(l)=0.4 m` , Speed (v) = 7 m//s and magnetic field (B) = 0.9 `Wb//m^(2)`. Induced e.m.f. `(V)=Blv sin theta = 0.9xx0.4xx7xx sin 90^(@)=2.52 V`.