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The mutual inductance of a pair of coils...

The mutual inductance of a pair of coils, each of N turns, is M henry. If a current of I ampere in one of the coils is brought to zero in t second, the emf induced per turn in the other coil, in volt, will be

A

`(MI)/(t)`

B

`(NMI)/(t)`

C

`(MN)/(It)`

D

`(MI)/(Nt)`

Text Solution

Verified by Experts

The correct Answer is:
A

`E=(d)/(dt)(NMI)rArr E=NM(dI)/(dt)rArr E=(NMI)/(t)`
emf induced per unit turn `=(E )/(N)=(MI)/(t)`
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