A long solenoid has `500` turns. When a current of `2A` is passed through it, the resulting magnetic flux linked with each turn of the solenoid is `4xx10^(-3)Wb` . The self-inductance of the solenoid is

Options

A. 2.5 henry
B. 2.0 henry
C. 1.0 henry
D. 40 henry

Answer

C

Explanation

Total number of turns in the solenoid, N = 500
Current, I = 2 A.
Magnetic flux limked with each turn `=4xx10^(-3)Wb`
As, `phi = LI` or `N phi = LI rArr L = (N phi)/(I)`
`=(500xx4xx10^(-3))/(2)` henry = 1 H.