A generator has an e.m.f. of 440 Volt and internal resistance of 4000 hm. Its terminals are connected to a load of 4000 ohm. The voltage across the load is

Options

A. 220 volt
B. 440 volt
C. 200 volt
D. 400 volt

Explanation

To solve the problem step by step, we will follow the principles of electromagnetism, specifically Ohm's Law and the concept of total resistance in a circuit.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Electromotive Force (e.m.f) of the generator, \( E = 440 \, \text{V} \)
- Internal resistance of the generator, \( R_{internal} = 4000 \, \Omega \)
- Load resistance, \( R_{load} = 4000 \, \Omega \)

2. **Calculate Total Resistance in the Circuit:**
- The total resistance \( R_T \) in the circuit is the sum of the internal resistance and the load resistance.
\[ R_T = R_{internal} + R_{load} = 4000 \, \Omega + 4000 \, \Omega = 8000 \, \Omega \]

3. **Calculate the Current in the Circuit:**
- Using Ohm's Law, the current \( I \) flowing through the circuit can be calculated using the formula:
\[ I = \frac{E}{R_T} = \frac{440 \, \text{V}}{8000 \, \Omega} \]
- Performing the calculation:
\[ I = \frac{440}{8000} = 0.055 \, \text{A} \]

4. **Calculate the Voltage Across the Load:**
- The voltage across the load \( V_L \) can be calculated using Ohm's Law again:
\[ V_L = I \times R_{load} = 0.055 \, \text{A} \times 4000 \, \Omega \]
- Performing the calculation:
\[ V_L = 0.055 \times 4000 = 220 \, \text{V} \]

5. **Final Answer:**
- The voltage across the load is \( V_L = 220 \, \text{V} \).