A 10-meter wire is kept in east-west direction. It is falling down with a speed of `5.0 "meter"//"second"`, perpendicular to the horizontal component of earth's magnetic field of `0.30 x×10^(-4) "weber"//"meter"^(2)`. The momentary potential difference induced between the ends of the wire will be

Options

A. 0.0015 V
B. 0.015 V
C. 0.15 V
D. 1.5 V

Answer

A

Explanation

If a wire, l meter in length, perpendicular to a magnetic field of B weber/`"meter"^(2)` with a velocity of v meter/second, then the e.m.f. induced in the wire is given by
`V=Bvl` volt,
Here, `B=0.30xx10^(-4)"weber/meter"^(2)`,
v = 5.0 meter/second and 1 = 10 meter.
`therefore B=0.30xx10^(-4)xx5.0xx10=0.0015` volt.