Home
Class 12
PHYSICS
Using an AC voltmeter, the potential dif...

Using an AC voltmeter, the potential difference in the electrical line in a house is read to be 234 volt. If the line frequency is known to be 50 cycle per sec, the equation for the line voltage is

A

`V = 165 sin (100 pi t)`

B

`V = 331 sin (100 pi t)`

C

`V = 220 sin (100 pi t)`

D

`V = 440 sin (100 pi t)`

Text Solution

Verified by Experts

The correct Answer is:
B
`V = V_(0)sin omega t`
Volatge in r.m.s value
`V_(0) = sqrt 2 xx 234 V = 331 volt` and `omega t = 2 pi n t = 2 pi xx 50 xx t = 100 pi t`
Thus, the equation of line voltage is given by `V = 331 sin (100 pi t)`
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    DISHA PUBLICATION|Exercise Exercise - 1 : CONCEPT BUILDER (Topic 2: A.C Circuits and Power Factor)|31 Videos

  • ALTERNATING CURRENT

    DISHA PUBLICATION|Exercise Exercise - 1 : CONCEPT BUILDER (Topic 3 : Transformers and LC Oscillations)|19 Videos

  • ALTERNATING CURRENT

    DISHA PUBLICATION|Exercise Exercise -2 : Concept Applicator|30 Videos

  • ATOMS

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT APPLICATOR|30 Videos

Similar Questions

Explore conceptually related problems

Using an ac voltmeter, the potential difference in the electrical line in a house is read to be 234 V. If the line freqency is known to be 50 cycles per second, the equation for the line voltage is

Using an A.C. voltmeter, the Peak potential difference in the electrical line in a house is read to be 234 volts. If the line frequency is known to be 50 cycles per second, the equation for the line voltage is

The household supply voltage as measured by an a.c. voltmeter is 200 meter is 220 volts. If the frequency of a.c. Supply is 50 Hz, then the equation of the line voltage, will be

With an ac input from 50 Hz power line, the ripple frequency is

An inductor, a capacitor and a resistor are connected in series to an a.c. supply. When measured with an a.c. voltmeter, the potential difference across the inductor, capacitor and resistor are respectively 90 volt, 60 volt and 40 volt. Then the supply voltage is

An inductor, a capacitor and a resistor are connected in series to an a.c. supply. When measured with an a.c. voltmeter, the potential difference across the inductor, capacitor and resistor are resspectively 90 volt, 60 volt and 40 volt. Then the supply voltage is

In a Coolidge tube, the potential difference used to accelerate the electrons is increased from 24. 8 kV to 49.6 kV . As a result, the difference between the wavelength of K_(alpha) -line and minimum wavelength becomes two times. The initial wavelength of the K_(alpha) line is [Take (hc)/(e) = 12 .4 kV Å ]

A photoelectric cell is connected to a source of variable potential difference, connected across it and the photoelectric current resulting (muA) is plotted against the applied potential difference (V). The graph in the broken line represents one for a given frequency and intensity of the incident radiation. If the frequency is increased and the intensity is reduced. Which of the following graphs of unbroken line represents the new situation?

A photoelectric cell is connected to a source of variable potential difference, connected across it and the photoelectric current resulting (muA) is plotted against the applied potential difference (V). The graph in the broken line represents one for a given frequency and intensity of the incident radiation . If the frequency is increased and the intensity is reduced, which of the following graphs of unbroken line represents the new situation?

DISHA PUBLICATION-ALTERNATING CURRENT -Exercise - 1 : CONCEPT BUILDER (TOPIC 1: Alternating Current, Voltage and Power)
  1. Alternating current can not be measured by D.C. Ammeter because

    Text Solution

    |

  2. In an AC circuit, peak value of voltage is 423 volts. Its effective vo...

    Text Solution

    |

  3. The voltage time (V-t) graph for triangular wave having peak value V(0...

    Text Solution

    |

  4. The heat produced in a given resistor in a given time by the sinusoida...

    Text Solution

    |

  5. A sinusoidal ac current flows through a resistor of resistance R . If ...

    Text Solution

    |

  6. Current time graph of different source is given which one will have R....

    Text Solution

    |

  7. Average voltage for the given source is :

    Text Solution

    |

  8. The current I passed in any instruement in alternating current circuit...

    Text Solution

    |

  9. The voltage of an AC supply varies with time (t) as V = 120 sin 100 pi...

    Text Solution

    |

  10. An alternating e.m.f. of angular frequency omega is applied across an ...

    Text Solution

    |

  11. Using an AC voltmeter, the potential difference in the electrical line...

    Text Solution

    |

  12. An alternating current is given by I = i1 cos omegat + i2 sin omegat...

    Text Solution

    |

  13. Determine the rms value of a semi-circular current wave which has a ma...

    Text Solution

    |

  14. The rms value of the function shown in figure if it its given that for...

    Text Solution

    |

  15. Figure shows one cycle of an alternating current with the segments AB,...

    Text Solution

    |

  16. A resistance of 20 ohm is connected to a source of an alternating pote...

    Text Solution

    |

  17. The rms value of the emf given by E = 8 sin omegat + 6 sin 2omegat .

    Text Solution

    |

  18. An AC voltage source has an output of V = 200 sin 2 pi ft. This source...

    Text Solution

    |

  19. The r.m.s value of an a.c of 59 Hz is 10 A. The time taken by the alte...

    Text Solution

    |

  20. Using an AC voltmeter, the potential difference in the electrical line...

    Text Solution

    |