For the circuit shown in the fig., the current through the inductor is 0.9 A while the current through the condenser is 0.4 A. Then

Options

A. current drawn from generator I = 1.13 A
B. `omega = 1/(1.5 LC)`
C. `I = 0.5 A`
D. `I = 0.6 A`

Answer

C

Explanation

The current drawn by inductor and capacitor will be in opposite phase.Hence net current drawn from generator = `I_(L) - I_(C) = 0.9 - 0.4 = 0.5 amp`.