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A coil of 40 H inductance is connected i...

A coil of `40 H` inductance is connected in series with a resistance of `8` ohm and the combination is joined to the terminals of a `2 V` battery. The time constant of the circuit

A

20 seconds

B

5 seconds

C

1/5 seconds

D

40 seconds

Text Solution

Verified by Experts

The correct Answer is:
B
Time constant is `(L)/(R)`
Given, `L = 4011 & R = 8 Omega`
`therefore tau = (40)/(8) = 5 sec`.
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