An alternating current emf device has a smaller resistance than that of the resistive load, to increase the transfer of energy from the device to the load, a transformer will be connected between two.Then

Options

A. `N_(S)` should be greater than `N_(P)`
B. `N_(S)` should be less than `N_(P)`
C. `N_(S) = N_(P)`
D. none

Explanation

To solve the problem, we need to understand the relationship between the transformer, the voltage, and the turns of the coils. Here’s a step-by-step breakdown of the solution:

### Step 1: Understand the Problem
The problem states that an alternating current (AC) EMF device has a smaller resistance than that of the resistive load. To increase the transfer of energy from the device to the load, a transformer will be connected between the two.

### Step 2: Identify the Goal
The goal is to increase the energy transfer from the AC EMF device to the resistive load. To achieve this, we need to manipulate the voltage across the load.

### Step 3: Recall Transformer Basics
A transformer works on the principle of electromagnetic induction and consists of two coils: the primary coil (input) and the secondary coil (output). The relationship between the voltages and the number of turns in the coils is given by the formula:
\[ \frac{V_s}{V_p} = \frac{N_s}{N_p} \]
where:
- \( V_s \) = Voltage across the secondary coil
- \( V_p \) = Voltage across the primary coil
- \( N_s \) = Number of turns in the secondary coil
- \( N_p \) = Number of turns in the primary coil

### Step 4: Increase the Secondary Voltage
To increase the energy transfer to the load, we need to increase the voltage across the secondary coil (\( V_s \)). According to the transformer equation, if we want \( V_s \) to be greater than \( V_p \), then we need:
\[ \frac{N_s}{N_p} > 1 \]
This implies that:
\[ N_s > N_p \]
Thus, the number of turns in the secondary coil must be greater than that in the primary coil.

### Step 5: Conclusion
Therefore, to increase the energy transfer from the AC EMF device to the resistive load, the number of turns in the secondary coil (\( N_s \)) should be greater than the number of turns in the primary coil (\( N_p \)).

### Final Answer
The correct statement is: \( N_s > N_p \).

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