In the circuit shown in fig. R is a pure resistor, L is an inductor of ngligibe resistance (as compared to R), S is a 100 V , 50 Hz ac source of negligible resistnce. With either kiy `(K-1) `alone or `(K_2)` alone closed, the current is `(I_0)`. If the source os changed to 100 V, 100 Hz the current with `(K_1)` alone closed and with `(K_2)` alone closed will be, respectively.

Options

A. `I_(0), (I_(0))/(2)`
B. `I_(0), 2I_(0)`
C. `2I_(0), I_(0)`
D. `2I_(0), (I_(0))/(2)`

Answer

A

Explanation

Current remains unchanged in R.However, it becomes half in L, because reactance is doubled on doubling the frequency.