In given circuit capacitorinitially uncharged.Now at t = 0 switch S is closed then current given by source at any time t is

Options

A. `(2)/(R)(1 - e^((-2t)/(CR)))`
B. `(epsilon)/(2R)(1 + e^((-2t)/(CR)))`
C. `(epsilon)/(2R)(1 - e^((-2t)/(CR)))`
D. `(2epsilon)/(R)(1 - e^((-2t)/(CR)))`

Answer

B

Explanation

`Q = (EC)/(2)(1 - e^(-t/tau))`
`I_(2) = (epsilonC)/(2r) e^(-t/tau) = (epsilon)/(R) e^(-t/tau)`
`I_(1) = (Vc)/(R) = (epsilon/2)/(R)(1 - e^(-t/tau))`
`I_(1) = (epsilon)/(R) - e^(-t/tau) + (epsilon)/(2R) - (epsilon)/(2R) epsilon ^(-t/tau)`
`(epsilon)/(2R) (1 + e^(-t/tau)) = (epsilon)/(2R)(1 + e^(-2t)/(CR))`