An `AC` voltage is applied to a resistance `R` and an inductance `L` in series. If `R` and the inductive reactance are both equal to `3 Omega`, the phase difference between the applied voltage and the current in the circuit is

Options

A. `(pi)/(6)`
B. `(pi)/(4)`
C. `(pi)/(2)`
D. zero

Answer

B

Explanation

The phase difference `phi` is given by
`tan phi = (X_(L))/(R) = (3)/(3) = 1 Rightarrow phi = (pi)/(4)`