Both the nucleus and the atom of some element are in their respective first excited states. They get de-excited by emitting photons of wavelengths `lambda_(N) ,lambda_(A)` respectively. The ratio `(lambda_(N))/(lambda_(A))` is closest to :

Options

A. `10^(-6) `
B. 10
C. `10^(-1)`
D. `10^(-10)`

Answer

A

Explanation

Energy `E = (hc)/(lamda) , (lamda_N)/(lamda_a) = (E_a)/(E_N)`
Where `E_a` and `E_N` are energies of photons from atom and nucleus respectively . `E_N` is of the order of MeV = `10^6 eV` and `E_a` in few eV.
So `(lamda_N)/(lamda_a) = 10^(-6)`