If a proton and electron have the same de Broglie wavelength, then

Options

A. both have same kinetic energy
B. proton has more K.E. than electron
C. electron has more K.E. than proton
D. both have same velocity

Answer

C

Explanation

`lamda = (h)/(m_p v_p) = (h)/(m_e v_e) ` , then `m_p v_p = m_e v_e " or " (v_p)/(v_e) = (m_e)/(m_p)`
`(E_p)/(E_e) = (1/2 m_p v_p^2)/(1/2 m_e v_e^2) = (m_p)/(m_e) xx ((m_e)/(m_p))^2 = (m_e)/(m_p) lt 1`
` therefore E_p lt E_e`