The de-Broglie wavelength of neutron in thermal equilibrium at temperature T is

Options

A. `(30.8)/(sqrtT)Å`
B. `(3.08)/(sqrtT)Å`
C. `(0.308)/(sqrtT)Å`
D. `(0.0308)/(sqrtT)Å`

Answer

A

Explanation

From formula
`lamda = (h)/(sqrt(2mKT))`
` = (6.63 xx 10^(-34) )/(sqrt(2 xx 1.67 xx 10^(-27) xx 1.38 xx 10^(-23) T)) m` [ by placing value of h,m and k]
`= (30.8)/(sqrtT) Å`