Two identical photocathodes receive light of frequencies `f_1` and `f_2`. If the velocities of the photo electrons (of mass m ) coming out are respectively `v_1` and `v_2` then

Options

A. `v_1^2 -v_2^2 = (2h)/(m) (f_1 - f_2) `
B. `v_1 +v_2 = [ (2h)/(m) (f_1 + f_2)]^(1//2)`
C. `v_1^2 + v_2^2 = (2h)/(m) (f_1 + f_2)`
D. `v_1 - v_2 = [(2h)/(m) (f_1 - f_2)]^(1//2)`

Answer

A

Explanation

`v_1^2 -v_2^2 = (2h)/(m) (f_1 - f_2) `