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An electron is accelerated through a potential difference of V volt. It has a wavelength `lambda` associated with it. Through what potential difference an electron must be accelerated so that its de Broglie wavelength is the same as that of a proton? Take massof proton to be 1837 times larger than the mass of electron

A

V volt

B

1837 V volt

C

V/1837 volt

D

`sqrt(1837)V` volt

Text Solution

Verified by Experts

The correct Answer is:
C
`lamda = (h)/(sqrt(2mqV)) `
mV = constant
`V. = (V)/(1837) ` volt
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