A photon and an electron posses same de-Broglie wavelength. Given that c= speed of light and v=speed of electron, which of the following relations is correct? Here `E_(e) = KE` of elecron, `E_(ph) = KE` of photon, `p_(e) = momentum of electron , `p_(ph)` = momentum of photon:

Options

A. `E_e//E_(ph) = 2C//v`
B. `E//E_(ph) = v//2C `
C. `P_e//P_(ph) = 2 C//v`
D. `P_e//P_(ph) = C//v`

Answer

B

Explanation

`lamda_(ph) = lamda_e`
`(h)/(p_(ph)) = (h)/(p_e) rArr (E_(ph))/(C ) = (2E_e)/(v ) rArr (E_e)/(E_(ph)) = (v)/(2C)`