If the momentum of electron is changed by `P_(m)` then the de-Broglie wavelength associated with it changes by 0.50%. The initial momentum of electron will be:

Options

A. 200P
B. 400P
C. P/200
D. 100P

Answer

A

Explanation

The de-broglie.s wavelength associated with the moving electron `lamda = h/p`
now, according to problem
`(dlamda)/(lamda) = - (dp)/(p) = (0.5)/(100) = (p)/(p.) rArr p. = 200 P`