The energy required to remove the electron from a singly ionized Helium atom is `2.2` times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom ompletelyis:

Options

A. 20eV
B. 79eV
C. 109eV
D. 34eV

Answer

B

Explanation

Energy required to remove ` e^(-)` from singly ionized helium atom `= ((13.6 )z^2)/( 1^2) = 54.4 eV ( :. z=2)`
eneregy required to remove `e^(-)` from helium atom `- x e V ` according to question `, 54.4 eV = 2.2 x implies = 24.73 eV ` therefore energy required to ionize atom = (54.4 + 24.73 ) eV = 79.12 eV