In Rutherford's experiment, the number of `alpha`- particles scattered through an angle of `60^@` by a silverfoil is 200 per minute. When the silver foil is replaced by a copper foil of the same thickness, the number of a particles scattered through an angle of `60^@` per minute is:

Options

A. `(200 xx Z_(Cu))/(Z_(Ag))`
B. `200 xx ((Z_(cu))/(Z_(Ag)))^2`
C. `200 xx (Z_(Ag ))/( Z_(Cu))`
D. `200 xx((Z_(Ag))/( Z_(Cu)))`

Answer

B

Explanation

`200 xx ((Z_(cu))/(Z_(Ag)))^2`