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The distance between the a-particle and ...

The distance between the a-particle and target nucleus in an `alpha`-scattering experiment is equal to distance of closest approach, when the scattering angle is

A

`pi //2`

B

`pi`

C

`pi //4`

D

`pi //3`

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The correct Answer is:
To solve the problem, we need to understand the concept of the distance of closest approach in an alpha scattering experiment. The distance of closest approach is the minimum distance between the alpha particle and the target nucleus during the scattering process. ### Step-by-Step Solution: 1. **Understanding the Concept**: - In an alpha scattering experiment, an alpha particle approaches a target nucleus and experiences a repulsive force due to the positive charge of the nucleus. The distance of closest approach is the point at which the kinetic energy of the alpha particle is completely converted into potential energy due to this repulsion. 2. **Identifying the Scattering Angle**: - The scattering angle is defined as the angle through which the alpha particle is deflected after interacting with the target nucleus. When the alpha particle reaches the distance of closest approach, it momentarily comes to rest before being repelled back. 3. **Condition for Distance of Closest Approach**: - The distance between the alpha particle and the target nucleus is equal to the distance of closest approach when the alpha particle is directly approaching the nucleus and then reverses its direction. This occurs when the alpha particle is scattered back along the same path it came from. 4. **Calculating the Scattering Angle**: - When the alpha particle approaches the nucleus and reaches the distance of closest approach, it will scatter back in the opposite direction. This means that the scattering angle is 180 degrees (or π radians) because it has turned around completely. 5. **Conclusion**: - Therefore, the scattering angle when the distance between the alpha particle and the target nucleus is equal to the distance of closest approach is **π radians** (or 180 degrees). ### Final Answer: The scattering angle is π radians (or 180 degrees).
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DISHA PUBLICATION-ATOMS-EXERCISE-1: CONCEPT BUILDER (TOPICWISE)
  1. The distance of closest approach of a certain nucleus is 7.2 fm and it...

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  2. In Rutherford's experiment, the number of alpha- particles scattered t...

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  3. The distance between the a-particle and target nucleus in an alpha-sca...

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  4. In a Rutherford scattering experiment when a projectile of change Z(1)...

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  5. In Rutherford scattering experiment, the number of alpha-particles sca...

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  6. If in Rutherford's experiment, the number of particles scattered at 90...

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  7. In Rutherford scattering experiment, alpha-particles scattered at angl...

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  8. In the ground state in ...A... electrons are in stable equilibrium whi...

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  9. The angular speed of the electron in the n^(th) Bohr orbit of the hydr...

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  10. Which of the following statement concerning Bohr's model is //are tr...

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  11. According to Bohr's Model of hydrogen atom

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  12. when an electron jumps from the fourth orbit to the second orbit, one ...

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  13. Which of the following series in the spectrum of the hydrogen atom lie...

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  14. The balmer series for the H-atom can be ob-served

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  15. As the n (number of orbit) increases, the difference of energy between...

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  16. In Bohr's model of hydrogen atom, the period of revolution of the elec...

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  17. In a hydrogen atom following the Bohr's postulates the product of line...

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  18. The energy of electron in the nth orbit of hydrogen atom is expressed ...

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  19. In the hydrogen atom, an electron makes a transition from n=2 to n=1....

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  20. In terms of Rydberg constant R, the shortest wavelength in the Balmer ...

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