In a Rutherford scattering experiment when a projectile of change `Z_(1)` and mass `M_(1)` approaches s target nucleus of change `Z_(2)` and mass `M_(2)`, te distance of closed approach is `r_(0)`. The energy of the projectile is

Options

A. directly proportional to `Z_1, Z_2`
B. inversely proportional to `Z_1`
C. directly proportional to mass `M_1`
D. directly proportional to `M_1 xx M_2`

Answer

A

Explanation

The kinetic energy of the projectilic Is given by `1/2 mv^2 = (ze (2e ))/( 4 pi epsi_0 r_0) = (z _1 Z_2)/( 4 pi epsi_0 r_0)`
thus energy of the projectile is directly proportional to ` Z_1 , z_2`