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Taking Rydberg's constant R(H) = 1.097 x...

Taking Rydberg's constant `R_(H) = 1.097 xx 10^(7)m` first and second wavelength of Balmer series in hydrogen spectrum is

A

3000 Å

B

2960 Å

C

4280 Å

D

4863 Å

Text Solution

Verified by Experts

The correct Answer is:
D

`1/ lamda = R [(1)/( n_(1)^(2)) - (1)/(n_(2)^(2))]`
for second wavelength `n_1 =-2 ,n_2 =4implies lamda_2 = 4861 Å`
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DISHA PUBLICATION-ATOMS-EXERCISE-1: CONCEPT BUILDER (TOPICWISE)
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  16. The energy of a hydrogen atom in the ground state is -13.6 eV. The ene...

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  17. Electron in hydrogen atom first jumps from third excited state to seco...

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  19. The transition form the state n = 3 to n = 1 in a hydrogen-like atom r...

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