The ratio of the longest to shortest wavelength in Brackett series of hydrogen spectra is

Options

A. `25 //9`
B. `17//6`
C. `9//5`
D. `4//3`

Answer

A

Explanation

For Brackett series `(1 ) / ( lamda _(max )) = R [(1)/(4^2)- (1)/( 5 ^2) ] = (9 )/( 25 xx 16 ) R `
` and (1)/( lamda_(min )) = R [(1)/( 4^2 ) - (1)/( oo^2)]=R/( 16) implies ( lamda_(max ))/( lamda_(min )) = ( 25 )/(9)`