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If lamda(1) and lamda(2) are the wavelen...

If `lamda_(1) and lamda_(2)` are the wavelengths of the first members of the Lyman and Paschen series respectively, then `lamda_(1):lamda_(2)` is

A

`27//32`

B

`32//27`

C

4//9`

D

`9//4`

Text Solution

Verified by Experts

The correct Answer is:
A

`(1)/( lamda_(3-1))=R ((I )/(I^2 ) - (1)/(3^2)) =* 8R )/(9)`
`(1 )/( lamda_(2-1) ) = R ((I )/( I^2) - (1)/( 2^2))=(3R )/(4 ) implies (3R)/( 4 ) implies (lamda_(3-1))/(lamda _(2-1))=(27 )/( 32)`
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DISHA PUBLICATION-ATOMS-EXERCISE-1: CONCEPT BUILDER (TOPICWISE)
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  13. The average current due to an electron orbiting the proton in the n^(t...

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  15. The ionisation energy of hydrogen atom is 13.6 eV. Following Bohr's th...

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  16. The energy of a hydrogen atom in the ground state is -13.6 eV. The ene...

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  17. Electron in hydrogen atom first jumps from third excited state to seco...

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