Ultraviolet light of wavelength `lambda_(1)` and `lambda_(2)` (with `lambda_(2) gt lambda_(1)`) when allowed to fall on hydrogen atoms in their ground state is found to liberate electrons with kinetic energies `E_(1)` and `E_(2)` respectively. The value of the planck's constant can be found from the relation

Options

A. `h=|((KE_2 -KE_1)(lamda_1 +lamda_2))/(C (lamda_1-lamda_2))|`
B. `h=|(((KE_1 -KE _2) (lamda_2 -lamda_1))/( C lamda_1 lamda_2))|`
C. `h=|((KE_1 -KE_2)lamda_1 lamda_2)/(C(lamda_2 - lamda_1))|`
D. none of these

Answer

C

Explanation

`h=|((KE_1 -KE_2)lamda_1 lamda_2)/(C(lamda_2 - lamda_1))|`