The electron in a hydrogen atom jumps from ground state to the higher energy state where its velcoity is reduced to one-third its initial value. If the radius of the orbit in the ground state is `r` the radius of new orbit will be

Options

A. `3r`
B. `9r`
C. `r//3`
D. `r//9`

Answer

B

Explanation

`v= (1)/(137 ) c/n or v prop (1)/(n) `
since V is reduced to one - third , therefore n=3
Now `r prop n^2`