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If in hydrogen atom, radius of n^(th) Bo...

If in hydrogen atom, radius of `n^(th)` Bohr orbit is `r_n`., frequency of revolution of electron in `n^(th)` orbit is `f_n` choose the correct option.

A

B

C

D

Both (a) and (b)

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To solve the problem regarding the radius and frequency of the electron in the nth Bohr orbit of a hydrogen atom, we will follow these steps: ### Step 1: Understanding the Radius of the nth Bohr Orbit The radius \( r_n \) of the nth Bohr orbit is given by the formula: \[ r_n = a_0 \cdot n^2 \] where \( a_0 \) is the Bohr radius (approximately \( 0.529 \) Å for hydrogen), and \( n \) is the principal quantum number. ### Step 2: Analyzing the Relationship From the formula \( r_n = a_0 \cdot n^2 \), we can see that the radius \( r_n \) is directly proportional to the square of the quantum number \( n \). Therefore, if we plot \( r_n \) against \( n \), we will get a parabolic graph. ### Step 3: Frequency of Revolution of the Electron The frequency of revolution \( f_n \) can be derived from the time period \( T \) of one complete revolution: \[ f_n = \frac{1}{T} \] The time period \( T \) can be calculated as the distance traveled in one revolution divided by the speed of the electron. The distance traveled in one revolution is the circumference of the orbit: \[ T = \frac{2 \pi r_n}{v} \] where \( v \) is the speed of the electron. ### Step 4: Expressing Speed in Terms of n The speed \( v \) of the electron in the nth orbit can be related to \( n \) as: \[ v \propto \frac{Z}{n} \quad \text{(for hydrogen, } Z = 1\text{)} \] Thus, we can express \( v \) as: \[ v = k \cdot \frac{1}{n} \] where \( k \) is a constant. ### Step 5: Substituting into the Time Period Formula Substituting \( r_n \) and \( v \) into the time period formula: \[ T = \frac{2 \pi (a_0 n^2)}{k \cdot \frac{1}{n}} = \frac{2 \pi a_0 n^3}{k} \] Thus, the frequency becomes: \[ f_n = \frac{k}{2 \pi a_0 n^3} \] ### Step 6: Finding the Ratio of Frequencies To find the ratio of frequencies \( \frac{f_n}{f_1} \): \[ \frac{f_n}{f_1} = \frac{f_n}{k/(2 \pi a_0)} = \frac{1}{n^3} \] ### Step 7: Taking Logarithm Taking the logarithm of the ratio: \[ \log\left(\frac{f_n}{f_1}\right) = -3 \log(n) \] This indicates a linear relationship with a negative slope when plotted. ### Conclusion Based on the analysis: - The graph of \( r_n \) vs. \( n \) is parabolic. - The graph of \( \log\left(\frac{f_n}{f_1}\right) \) vs. \( \log(n) \) is a straight line with a negative slope. ### Final Answer The correct options are: - A: The graph of \( r_n \) vs. \( n \) is parabolic. - B: The graph of \( \log\left(\frac{f_n}{f_1}\right) \) vs. \( \log(n) \) is a straight line with a negative slope. Thus, the answer is **D: Both A and B are correct.**
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