The ionization enegry of the electron in the hydrogen atom in its ground state is `13.6 ev`. The atoms are excited to higher energy levels to emit radiations of `6` wavelengths. Maximum wavelength of emitted radiation corresponds to the transition between

Options

A. n=3 to n= 1 states
B. n=2 to n= 1 states
C. n=4 to n = 3 states
D. n=3 to n=2 states

Answer

C

Explanation

`(n(n-1))/(2) =6`

` n^2 -n-12 =0`
` (n-4 ) (n+3) =0`
` or `n=4