Two deuterons udnergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron = 1.1 MeV and for helium = 7.0 MeV)

Options

A. 30.2 MeV
B. 32.4 Me V
C. 23.6 Me V
D. 25.8 MeV

Answer

C

Explanation

`""_(1) H^(2) + ""_(1) H^(2) to ""_(2) He^(4)`
Total binding energy of two deuterium nuclei = `1.1 xx 4 = 4.4` Me V
Binding energy of a `(""_(2) He^(4))` nuclei = `4 xx 7 = 28` Me V
Energy released in this process = `28 - 4.4 = 23.6` MeV