The above is a plate of binding energy per nucleon `E_(0)` against the nuclear mass `M, A, B,C,D,E,F` correspond to different nuclei Consider four reactions:

Options

A. (i) and (iii)
B. (ii) and (iv)
C. (ii) and (iii)
D. (i) and (iv)

Answer

D

Explanation

For `A + B to C + epsilon , epsilon` is positive . This is because `E_(b)` for C is greater than the `E_(b)` for A and B .
Again for `F to D + E + epsilon , epsilon` is positive . This is because `E_(b)` for D and E is greater than `E_(b)` for F