When Uranium is bombarded with neutrons , it undergoes fission . The fission reaction can be written as :
`""_(92) U^(235) + ""_(0) n^(1) to ""_(56) Ba^(141) + ""_(36) Kr^(92) + 3x + Q` (energy)
where three particles named x are produced and energy Q is released . What is the name of the particle x ?

Options

A. electron
B. `alpha`- particle
C. neutron
D. neutrino

Explanation

To solve the problem, we need to identify the particle \( x \) produced in the fission reaction of Uranium-235 when it is bombarded with neutrons. The reaction can be represented as follows:

\[ _{92}^{235}U + _{0}^{1}n \rightarrow _{56}^{141}Ba + _{36}^{92}Kr + 3x + Q \]

### Step-by-Step Solution:

1. **Identify the Reactants and Products:**
- Reactants: Uranium-235 (U-235) and a neutron (n).
- Products: Barium-141 (Ba-141), Krypton-92 (Kr-92), three particles \( x \), and energy \( Q \).

2. **Balance the Atomic Numbers:**
- The atomic number of Uranium is 92, and the neutron has an atomic number of 0.
- On the product side, Barium has an atomic number of 56 and Krypton has an atomic number of 36.
- The total atomic number on the product side must equal the total atomic number on the reactant side.

\[ 92 = 56 + 36 + 3A \]
where \( A \) is the atomic number of particle \( x \).

Rearranging gives:
\[ 92 = 92 + 3A \implies 3A = 0 \implies A = 0 \]

3. **Balance the Mass Numbers:**
- The mass number of Uranium-235 is 235, and the neutron has a mass number of 1.
- On the product side, Barium has a mass number of 141 and Krypton has a mass number of 92.
- The total mass number on the product side must equal the total mass number on the reactant side.

\[ 236 = 141 + 92 + 3B \]
where \( B \) is the mass number of particle \( x \).

Rearranging gives:
\[ 236 = 233 + 3B \implies 3B = 3 \implies B = 1 \]

4. **Identify the Particle \( x \):**
- From the calculations, we found that the atomic number \( A = 0 \) and the mass number \( B = 1 \).
- This corresponds to a neutron, which is represented as \( _{0}^{1}n \).

### Conclusion:
The particle \( x \) produced in the fission reaction is a **neutron**.