Energy released in the fission of a single `._92 U^235` nucleus is `200 MeV`. The fission rate of a `._92 U^235` fuelled reactor operating at a power level of `5 W` is.

Options

A. `1.56 xx 10^(-10) s^(-1)`
B. `1.56 xx 10^(11) s^(-1)`
C. `1.56 xx 10^(-16) s^(-1)`
D. `1.56 xx 10^(-17) s^(-1)`

Answer

B

Explanation

Fission rate = `("total power ")/(("energy")/("fission")) = (5)/(200 xx 1.6 xx 10^(-13)) = 1.56 xx 10^(11) s^(-1)`