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If M(A,Z), M(p)and M(n) denote the masse...

If `M(A,Z)`, `M_(p)and M_(n)` denote the masses of the nucleus `._(Z)X^(A)`, proton and neutron respectively in units of U (where`1U=931MeV//c^(2)`) and B.E. represents its B.E. in MeV, then

A

M( A , Z) = `ZM_(p) + (A - Z) M_(n) - BE//c^(2)`

B

`M(A , Z) = ZM_(p) + (A - Z) M_(n) + BE`

C

`M(A , Z) = ZM_(p) + (A - Z) M_n - BE`

D

`M (A , Z) = ZM_(p) + (A - Z) M_(n) + BE//c^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

Mass defect = `ZM_(P) + (A - Z) M_(n) - M (A ,Z)` or `, (B.E.)/(c^(2)) = ZM_(p) + (A - Z) M_(n) - M (A, Z)`
`therefore M (A , Z) = ZM_(p) + (A - Z) M_(n) - (B.E.)/(c^(2))`
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DISHA PUBLICATION-NUCLEI-EXERCISE - 1 CONCEPT BUILDER
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