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In radioactive transformation ""(92)U^(2...

In radioactive transformation `""_(92)U^(235) to ""_(82)Pb^(206)` , the number of `alpha` and `beta` particles emitted are

A

`10 alpha , 6 beta`

B

4 protons , 8 neutrons

C

6 electrons , 8 protons

D

`6 beta , 8 alpha`

Text Solution

Verified by Experts

The correct Answer is:
D
The number of `alpha`- particles = `(238 - 206)/(4) = 8`
If n be the number of `beta` - particles emitted then `92 - 8 xx 2 + n xx 1 = 82`
`therefore n = 6`
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