The ratio of half-life times of two elements `A` and `B` is `(T_(A))/(T_(B))`. The ratio of respective decay constant `(lambda_(A))/(lambda_(B))`,is

Options

A. `T_(B)// T_(A)`
B. `T_(A) // T_(B)`
C. `(T_(A) + T_(B))/(T_(A))`
D. `(T_(A) - T_(B))/(T_(A))`

Answer

A

Explanation

`T_(1//2) = (ln 2)/(lambda) therefore lambda = (ln 2)/(T_(1//2))`
`implies lambda _(A) = (ln 2)/(T_(A)) , lambda _(B) = (ln 2)/(T_(B)) implies (lambda_(A))/(lambda_(B)) = (T_(B))/(T_(A))`