The masses of neutron and proton are `1.0087` a.m.u. and `1.0073` a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particle) of mass `4.0015`a.m.u. The binding energy of the helium nucleus will be `(1 a.m.u. = 931 MeV)`.

Options

A. 28.4 Me V
B. 20.8 MeV
C. 27.3 Me V
D. 14.2 Me V

Answer

A

Explanation

B.E. `= Delta mc^(2) = Delta xx 931 Me V `
`=[2(1.0087 + 1.0073) - 4.0015] xx 931 = 28.4 MeV`