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The mass of a .(3)^(7) Li nucleus is 0.0...

The mass of a `._(3)^(7) Li` nucleus is `0.042 u` less than the sum of the masses of all its nucleons. The binding energy per nucleon of `._(3)^(7)Li` nucleus is nearly

A

46 MeV

B

5.6 MeV

C

3.9 MeV

D

23 MeV

Text Solution

Verified by Experts

The correct Answer is:
B
B.E = `0.042 xx 931 = 42 MeV`
Number of nucleons in `""_(3)^(7) Li` is 7
`therefore` B.E./nucleon = `(42)/(7) = 6` Me V= 5.6 Me V
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