Assume that a neutron breaks into a proton and an electron. The energy released during this process is (mass of neutron = `1.6725 xx 10^(-27)` kg, mass of proton = `1.6725 xx 10^(-27) kg`, mass of electron `= 9 xx 10^(-31) kg)`

Options

A. 0.73 MeV
B. 7.10 MeV
C. 6.30 Me V
D. 5.4 Me V

Answer

A

Explanation

`""_(0) ^(1) n to ""_(1)^(1) H + ""_(-1) e^(0) + barv + Q`
The mass defect during the process `Delta m = m_(n) -m_(H) - m_(e)`
`= 1.675 xx 10^(-27) - (1.675 xx 10^(-27) + 9 xx 10^(-27) + 9 xx 10^(-31)` kg)
`=-9 xx 10^(-31)` kg
The energy released during the process
`E = Delta mc^(2)`
`E = 9 xx 10^(-31) xx 9 xx 10^(16) = 81 xx 10^(-15)` Joules
`E = (81 xx 10^(-15))/(1.6 xx 10^(-19)) = 0.51` 1 MeV