The C - H bond distance of `CH_(3)-C-=C-CH(CH_(3))_(2)` is

Options

A. 4 - methyl - 2 - pentyne
B. 4 , -4 - dimethyl - 2 - butyne
C. methyl isopropyl acetylene
D. 2 - methyl - 4 - pentyne

Answer

To determine the C-H bond distance in the compound `CH3-C≡C-CH(CH3)2`, we first need to analyze the structure of the compound and understand the nature of the bonds involved.

### Step-by-Step Solution:

1. **Identify the Structure**:
The compound `CH3-C≡C-CH(CH3)2` consists of a carbon chain with a triple bond between the second and third carbon atoms. The structure can be visualized as follows:
```
CH3 - C ≡ C - C - CH3
|
CH3
```

2. **Determine the Hybridization**:
- The carbon atoms involved in the triple bond (C2 and C3) are sp hybridized.
- The terminal carbon (C1) and the carbon connected to the substituent (C4) are sp3 hybridized.

3. **C-H Bond Distance**:
- The C-H bond distance can vary depending on the hybridization of the carbon atom.
- For sp3 hybridized carbon (C1 and C4), the C-H bond distance is typically around 1.09 Å (angstroms).
- For sp hybridized carbon (C2), the C-H bond distance is shorter, approximately 1.06 Å.

4. **Conclusion**:
- Since the question asks for the C-H bond distance in the compound, we need to specify which C-H bond we are referring to.
- The C-H bond distances for the sp3 hybridized carbons (C1 and C4) are approximately 1.09 Å, while for the sp hybridized carbon (C2), it is approximately 1.06 Å.

### Final Answer:
The C-H bond distance in the compound `CH3-C≡C-CH(CH3)2` is approximately 1.09 Å for sp3 hybridized carbons and 1.06 Å for the sp hybridized carbon.