Home
Class 12
CHEMISTRY
CF2 = CF2 is a unit of...

`CF_2 = CF_2` is a unit of

A

teflon

B

buna-S

C

bakelite

D

polythene

Text Solution

AI Generated Solution

The correct Answer is:
To determine what the unit \( CF_2 = CF_2 \) represents, we can follow these steps: ### Step 1: Identify the Compound The formula \( CF_2 = CF_2 \) indicates a double bond between two carbon atoms, each bonded to two fluorine atoms. This compound is known as tetrafluoroethylene. ### Step 2: Understand the Structure In tetrafluoroethylene, each carbon atom is bonded to two fluorine atoms instead of hydrogen atoms, which is the case in ethylene (C2H4). The presence of fluorine atoms gives it unique properties. ### Step 3: Relate to Polymers Tetrafluoroethylene can undergo polymerization, which means that many tetrafluoroethylene units can join together to form a larger molecule, known as a polymer. The polymer formed from tetrafluoroethylene is called polytetrafluoroethylene (PTFE), commonly known as Teflon. ### Step 4: Identify the Correct Option Given the options: 1. Tetrafluoroethylene 2. CF2 3. Tetrafluoroethylene 4. CF2 5. CF2 6. CF2 7. CF2 8. CF2 9. CF2 10. Teflon 11. Polymer of Tetrafluoroethylene Since tetrafluoroethylene is the monomer that polymerizes to form Teflon, we can conclude that \( CF_2 = CF_2 \) is indeed a unit of Teflon. ### Conclusion Thus, the answer is that \( CF_2 = CF_2 \) is a unit of **Teflon**. ---
To determine what the unit \( CF_2 = CF_2 \) represents, we can follow these steps: ### Step 1: Identify the Compound The formula \( CF_2 = CF_2 \) indicates a double bond between two carbon atoms, each bonded to two fluorine atoms. This compound is known as tetrafluoroethylene. ### Step 2: Understand the Structure In tetrafluoroethylene, each carbon atom is bonded to two fluorine atoms instead of hydrogen atoms, which is the case in ethylene (C2H4). The presence of fluorine atoms gives it unique properties. ...
Promotional Banner

Topper's Solved these Questions

  • POLYMERS

    DISHA PUBLICATION|Exercise EXERCISE -2 : CONCEPT APPLICATOR|30 Videos

  • POLYMERS

    DISHA PUBLICATION|Exercise EXERCISE -2 : CONCEPT APPLICATOR|30 Videos

  • ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES

    DISHA PUBLICATION|Exercise Exercise - 2 : Concept Applicator|30 Videos

  • REDOX REACTIONS

    DISHA PUBLICATION|Exercise EXERCISE-2 : CONCEPT APPLICATOR|30 Videos

Similar Questions

Explore conceptually related problems

CF_(2) = CF_(2) is a monomer of

F_(2)C = CF_(2) is a monomer of

F_(2)C = CF_(2) is a monomer of:

CF_(2)CI_(2) is used as an // a

n(CF_2 = CF_2) overset((NH_4)_2 SO_4)to X , Here , X is

F_(2)C=CF-CF = CF_(2) rarr F_(2)underset(FC=)underset(|)(C)-underset(CF)underset(|)(CF_(2)) For this reaction (ring closure), DeltaH =- 49 kJ mol^(-1), DeltaS =- 40.2 J K^(-1) mol^(-1).Up to what temperature is the forward reaction spontaneous?

CF_(3) NH_(2) is not a base, whereas CH_(3)NH_(2) is a base. What is the reason ?

nCF_(2)=CF_(2) overset(A)underset(triangle"/"P)(to) (-CF_(2)-CF_(2)-)n Teflon.