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The condensation of hexamethylenediamine...

The condensation of hexamethylenediamine with sebacoyl chloride at 525 K gives

A

nylon-6,20

B

nylon-6,01

C

nylon-6,10

D

None of these

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The correct Answer is:
To solve the question regarding the condensation of hexamethylenediamine with sebacoyl chloride at 525 K, we will follow these steps: ### Step 1: Identify the Reactants - **Hexamethylenediamine**: This is a diamine with the formula \( H_2N(CH_2)_6NH_2 \). It contains two amine groups (-NH2). - **Sebacoyl Chloride**: This is a dicarboxylic acid chloride with the formula \( Cl-(CO-(CH_2)_8-CO) \). It contains two acyl chloride groups. ### Step 2: Understand the Reaction Type - The reaction between hexamethylenediamine and sebacoyl chloride is a **condensation polymerization** reaction. In this type of reaction, monomers combine to form a polymer while releasing small molecules, typically water or hydrogen chloride (HCl). ### Step 3: Write the Reaction - When hexamethylenediamine reacts with sebacoyl chloride, the amine groups react with the acyl chloride groups to form amide bonds. The reaction can be summarized as: \[ n \, H_2N(CH_2)_6NH_2 + n \, Cl-(CO-(CH_2)_8-CO) \rightarrow \text{Polymer} + n \, HCl \] ### Step 4: Determine the Structure of the Polymer - The repeating unit of the polymer will consist of the amide bond formed between the hexamethylenediamine and sebacoyl chloride. The structure of the repeating unit can be represented as: \[ -NH-(CH_2)_6-NH-CO-(CH_2)_8-CO- \] ### Step 5: Count the Carbon Atoms - In hexamethylenediamine, there are 6 carbon atoms. - In sebacoyl chloride, there are 8 carbon atoms. - Therefore, the total number of carbon atoms in the repeating unit of the polymer is \( 6 + 8 = 14 \). ### Step 6: Name the Polymer - The polymer formed from hexamethylenediamine and sebacoyl chloride is known as **Nylon 610**. The naming convention for nylons is based on the number of carbon atoms in the diamine and the dicarboxylic acid used. ### Final Answer The condensation of hexamethylenediamine with sebacoyl chloride at 525 K gives **Nylon 610**. ---

To solve the question regarding the condensation of hexamethylenediamine with sebacoyl chloride at 525 K, we will follow these steps: ### Step 1: Identify the Reactants - **Hexamethylenediamine**: This is a diamine with the formula \( H_2N(CH_2)_6NH_2 \). It contains two amine groups (-NH2). - **Sebacoyl Chloride**: This is a dicarboxylic acid chloride with the formula \( Cl-(CO-(CH_2)_8-CO) \). It contains two acyl chloride groups. ### Step 2: Understand the Reaction Type - The reaction between hexamethylenediamine and sebacoyl chloride is a **condensation polymerization** reaction. In this type of reaction, monomers combine to form a polymer while releasing small molecules, typically water or hydrogen chloride (HCl). ...
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DISHA PUBLICATION-POLYMERS -EXERCISE -2 : CONCEPT APPLICATOR
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  12. Which of the following is not correct regarding terylene?

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  16. Given th polymers, A = Nylon-6,6, B= Buna-S, C = Polythene Arrange...

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  17. Which one of the following statements is not true ?

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  18. The compound which cannot be used as a plasticizer, is

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  19. When condensation product of hexamethylenediamine and adipic acid is h...

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  20. Of the following which one is classified as polyester polymer?

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