Two labourers a and b are paid a total of Rs. 1120 per day. If a is paid 180 percent of what is paid to b. How much is b paid ?

Options

A. 400
B. 720
C. 500
D. 620

Answer

To solve the problem, we need to find out how much laborer B is paid given that laborer A is paid 180% of what laborer B receives and their total combined payment is Rs. 1120.

### Step-by-Step Solution:

1. **Define the Variables:**
- Let the amount paid to laborer B be \( x \) (in Rs).
- Since laborer A is paid 180% of what B is paid, we can express A's payment as:
\[ A = 1.8x \]

2. **Set Up the Equation:**
- The total payment for both laborers A and B is given as Rs. 1120. Therefore, we can write the equation:
\[ A + B = 1120 \]
- Substituting the expressions for A and B, we have:
\[ 1.8x + x = 1120 \]

3. **Combine Like Terms:**
- Combine the terms on the left side:
\[ 2.8x = 1120 \]

4. **Solve for \( x \):**
- To find \( x \), divide both sides of the equation by 2.8:
\[ x = \frac{1120}{2.8} \]

5. **Calculate \( x \):**
- Performing the division:
\[ x = 400 \]

6. **Conclusion:**
- Therefore, the amount paid to laborer B is Rs. 400.

### Final Answer:
Laborer B is paid Rs. 400.