If `alpha` and `beta` are the roots of quadratic equation`x^2+ px + q=0` and `gamma` and `delta` are the roots of `x^2 + p x-r=0` then `(alpha-gamma)(alpha-delta)`

if alpha,beta are the roots of quadratic equation x^(2)+px+q=0 then gamma,delta are the roots of x^(2)+px-r=0, then (alpha-gamma)(alpha-delta)

If alpha, beta are the roots of the quadratic equation x ^(2)+ px+q=0 and gamma, delta are the roots of x ^(2)+px-r =0 then (alpha- gamma ) (alpha -delta ) is equal to :

If alpha, beta are the roots of quadratic equation x^(2)+px+q=0 and gamma, delta are the roots of x^(2)=px+r=0, then (alpha-gamma).(alpha-delta) is equal to

If alpha, beta are the roots of the quadratic equation x ^(2)+ px+q=0 and gamma, delta are the roots of x ^(2)+px-r =0 then (alpha- gamma ) (alpha -delta ) is equal to :

If alpha , beta are the roots of x^2 +px -q=0 and gamma , delta are the roots of x^2 +px+r=0 then (alpha - gamma ) ( beta - gamma) ( alpha - delta ) ( beta- delta )=

If alpha and beta are the roots of x^(2) +px+q=0 and gamma , delta are the roots of x^(2) +rx+x=0 , then evaluate (alpha - gamma ) ( beta - gamma ) (alpha - delta ) ( beta - delta) in terms of p,q,r and s .

If alpha , beta are the roots of x^2 + px +1=0 and gamma , delta are the roots of x^2 +qx +1=0 then (alpha - gamma )(beta - gamma)(alpha + delta )( beta + delta )=

If alpha and beta are the roots of the equation x^(2) +px+1=0 , gamam , delta are the roots of (x^(2) +qx+1=0 , then , find ( alpha-gamma ) (beta - gamma ) ( alpha + delta )(beta + delta )

If alpha and beta are the roots of x^(2) +px+q=0 and gamma, delta are the roots of x^(2)+rx+s=0, then evaluate (alpha-gamma)(beta-gamma) (alpha-delta) (beta-deta) in terma of p,q, r and s.