The equivalent weight of `Na_(2) HPO_(4)` can be
a. `M//2` as base b. `M//1` as acid
c. Both (a) and (b) d. Neither (a) and (b)

The equivalent weight of KMnO_(4) in (a) neutral medium, (b) acidic medium and (c ) alkaline medium is M//.. ( where M is mol.wt. of KMnO_(4) )

Na_(2)HPO_(4)+ Reagent 'M'rarr white ppt. The reagent 'M' is:

In a A B C , A D is the bisector of /_A , meeting side B C at D . If A B=10 c m , A C=14 c m and B C=6c m , find B D and D C (ii) If A C=4. 2 c m , D C=6c m and B C=10 c m , find A B . (iii) If A B=5. 6 c m , A C=6c m and D C=3c m , find B C .

STATEMENT - 1 : Equivalent weight of a substance can never be greater than its molecular weight. STATEMENT - 2 : Equivalent weight of boric acid is (M)/(1) where M is the molecular weight. STATEMENT - 3 : Equivalent weight of H_(3)PO_(2) is (M)/(3) .

STATEMENT - 1 : Equivalent weight of a substance can never be greater than its molecular weight. STATEMENT - 2 : Equivalent weight of boric acid is (M)/(1) where M is the molecular weight. STATEMENT - 3 : Equivalent weight of H_(3)PO_(2) is (M)/(3) .

In a A B C , A D is the bisector of /_B A C . If A B=8c m , B D=6c m and D C=3c m . Find A C 4c m (b) 6c m (c) 3c m (d) 8c m

In a A B C , A D is the bisector of /_B A C . If A B=8c m , B D=6c m and D C=3c m . Find A C 4c m (b) 6c m (c) 3c m (d) 8c m

A: In the reaction 2NaOH + H_(3)PO_(4) to Na_(2)HPO_(4) + 2H_(2)O equivalent weight of H_(3)PO_(4) is (M)/(2) where M is its molecular weight. R: "Equivalent weight"= ("molecular weight")/("n-factor")

A: In the reaction 2NaOH + H_(3)PO_(4) to Na_(2)HPO_(4) + 2H_(2)O equivalent weight of H_(3)PO_(4) is (M)/(2) where M is its molecular weight. R: "Equivalent weight"= ("molecular weight")/("n-factor")