Home
Class 11
PHYSICS
In a car race, car A takes 4 s less than...

In a car race, car `A` takes `4 s` less than can `B` at the finish and passes the finishing point with a velcity `v` more than the car `B` . Assumung that the cars start form restand travel with constant accleration `a_(1)=4 m s^(-2)` and `a_(2) =1 m s^(-2)` respectively, find the velocity of `v` in m `s^(-1)`.

Promotional Banner

Similar Questions

Explore conceptually related problems

In a car race, car A takes a time of t s less than car B at the finish and passes the finishing point with a velocity v m/s more than the car B. Assuming that the cars start from rest and travel with constant acceleration a_1 and a_2 respectively, velocity v is given by

In a car race, A takes a time of t s, less than car B at the finish and passes the finishin point with a velocity v more than car B . Assuming that the cars stat from rest and travel with constant accelerations a_(1) and a_(2) . Respectively, show that vsqrt(a_(1) a_(2)t) .

In a car race, car A takes a time t less than car B at the finish and passes the finishing point with speed v more than that of the car B. Assuming that both the cars start from rest and travel with constant acceleration a_1 and a_2 respectively. Show that v=sqrt (a_1 a_2) t.

In a car race, car A takes a time t less than car B at the finish and passes the finishing point with speed v more than that of the car B. Assuming that both the cars start from rest and travel with constant acceleration a_1 and a_2 respectively. Show that v=sqrt (a_1 a_2) t.

In a car race, car A takes a time t less than car B at the finish and passes the finishing point with speed v more than that of the car B. Assuming that both the cars start from rest and travel with constant acceleration a_1 and a_2 respectively. Show that v=sqrt (a_1 a_2) t.

In a car race, car A takes time t less than car B and passes the finishing point with a velocity v more than the velocity with which car B passes the point. Assuming that the cars start from rest and travel with constant accelerations a_1 and a_2 show that v/t=sqrt(a_1a_2) .