If `tanx=1/7,tany=1/3`,then x+y is:

If 1-tanx/1+tanx=tany and x-y=pi/6 , then x, y are respectively

If tanx=2/3 and tany=3/4 then tan(x+y)=

In the following questions, write 'T' for truee and 'F' for false statements. If tanx + tany = 5 and tanx. tany =1/2 then cot(x+y) = 10

If x+y=pi/4 and tanx+tany=1, then

Solve :tanx+tany=1, x+y=pi//4

If tanx tany=a and x+y=2b show that tanx and tany are the roots of the equation z^2-(1-a)tan2b*z+a=0

If tanx tany=a and x+y=2b show that tanx and tany are the roots of the equation z^2-(1-a)tan2b*z+a=0

If tanx+tany=(5)/(6) and cotx+coty=5 , then tan(x+y) is

If (1-tanx)/(1+tanx)=tany and x-y = pi/6 , then x,y are respectively (A) (5pi)/24,pi/24 (B) -(7pi)/24, - (11pi)/24 (C) -(115pi)/24, (-119pi)/24 (D) none of these

If (1-tanx)/(1+tanx)=tany and x-y = pi/6 , then x,y are respectively (A) (5pi)/24,pi/24 (B) -(7pi)/24, - (11pi)/24 (C) -(115pi)/24, (-119pi)/24 (D) none of these