[12," If "(10)/(x+y)+(2)/(x-y)=4" and "(15)/(x+y)-(5)/(x-y)=-2,],[" then "quad " 1) "x-3,y=2],[" 3) "x=-3" y "quad " 2) "x=3,y=-2]

(4)/(x-y) + (1)/(x + y) = 3 , (2)/(x - y) - (3)/(x + y) = 5

Solve for x and y 2/(3x+2y)+3/(3x-2y)=17/5 5/(3x+2y)+1/(3x-2y)=2

Solve for x and y : (x, y ne 0) (10)/(2x+y)+(3)/(2x-y)=3, (15)/(2x+y)+(9)/(2x-y)=6

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

(x + 2) (x + 1) = (x -2) (x -3) (y+3)(y+2)=(y-1)(y-2)

Solve for x and y 2/(3x+2y)+3/(3x-2y)=17/5,5/(3x+2y)+1/(3x+2y)=6/5

{:("Column" A ,, "Column" B), ((3x^(2) - 5)- (2x^(2) - 5 + y^(2)) ,, (a) x^(2) + xy + y^(2)) , (9x^(2) - 16y^(2) ,, (b) 2) , ((x^(3) - y^(3))/(x-y) ,, (c) (9x + 16y) (9x - 16y)) , ("The degree of " (x + 2) (x+3) ,, (d) x^(2) - y^(2)) , (,, (e) 1) , (,, (f) (3x + 4y) (3x - 4y)):}

Solve the simultaneous equations : 10/(x+y) + 2/(x-y) = 4, 5/(x+y) -5/(3(x-y)) = (-2)/3

If (3x-y):x(4x+y)=5:12 then find (x^(2)+y^(2)):(x+y^(2))